[Ace-users] [ace-users] RE : RE : Notify in handle_signal
ext.zxerasoge002 at astrium.eads.net
Tue Feb 12 06:55:35 CST 2008
I probably should have started by this, but this deadlock is actually
I am using ACE 5.5, on RedHat EL 4, kernel Linux 2.6.9-55.0.2.ELsmp.
This program is a process manager, and can be told to kill all its
children process, which in turn produce a lot of SIGCHILD. At line 314,
the method handle_signal does this: getReactor()->notify( this );
Using gdb when the program is frozen, we get the following backtrace:
#0 0x0000003dffec09d0 in __write_nocancel () from /lib64/libc.so.6
#1 0x00002aaaaab642da in ACE::send (handle=5, buf=0x7fff0ec75790, n=16,
timeout=Variable "timeout" is not available.
) at ../../ace/OS_NS_unistd.inl:1343
#2 0x00002aaaaabe36ef in ACE_Select_Reactor_Notify::notify
(this=0x1089afa0, event_handler=0x108bd780, mask=4,
timeout=0x0) at ../../ace/Pipe.inl:26
#3 0x00002aaaaab728d4 in
(this=Variable "this" is not available.
#4 0x000000000046508f in ACALC::ProcessusManager::handle_signal
(this=0x108bd780, signum=17, si=0x7fff0ec75a50,
#5 0x00002aaaaabebb90 in ACE_Sig_Handler::dispatch (signum=17,
#6 <signal handler called>
When I greped on the ace source dir, I didn't find any reference to
ACE_HAS_REACTOR_NOTIFICATION_QUEUE in the config files, only in the
source files, so I guess the code for the unbounded notification queue
is not compiled in my case. Do I need to modify the config files by hand
to activate this ?
>From what I understand, this code only send one notification through the
pipe at a time, is that correct ?
That would solve the problem.
From: Johnny Willemsen [mailto:jwillemsen at remedy.nl]
Sent: Tuesday, February 12, 2008 11:05 AM
To: ZXERASOGE002, Ext
Subject: Re: [ace-users] RE : Notify in handle_signal
"ZXERASOGE002, Ext" <ext.zxerasoge002 at astrium.eads.net> wrote in message
news:<mailman.3582.1202807136.5286.ace-users at mail.cse.wustl.edu>...
Does anyone agree/disagree there is an issue here ?
I would really appreciate your help about this.
From: ZXERASOGE002, Ext
Sent: Friday, February 08, 2008 11:42 AM
To: ace-users at cse.wustl.edu
Subject: Notify in handle_signal
I have a question relative to the sample code in section 7.4 of
the ACE programmer's guide p158.
In a handle_signal callback, there is the following code:
There is a potential deadlock here. If for some reason the
process receives a lot of signals, and you don't process the
notifications quickly enough, the pipe can be full. Since this call is
blocking, and you are processing a signal, there is no chance your
process will unlock from this situation.
What is the best way to solve this ? Making a blocking call in
handle_signal looks like a mistake to me.
In the case of notify, if the pipe is full there's is no need to
wait, it will stay in this state as long as we are in handle_signal. I
see that we can add a timeout to the notify call, so at least it won't
wait forever. But as I said, if the pipe is full there is no need to
wait, so what is the best value for this timeout ? 1ms ? Are we 100%
sure this low value won't skip a write when the pipe is not full ?
Still, it means that every signal received when the pipe is full
will lock the process for 1ms, so we are slowing down the process
exactly when it is not fast enough to handle all the signals received.
Plus each handle_signal will be 1ms long, which is too much.
So is there a way to make a non blocking call in the notify ? or
a way to know if the pipe is full before trying to make a write on the
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